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Is gamblebot really cheating me this time or do I suck at card games?
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Observe this picture. from what I understand about blackjack gamblebot cheated.
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The second ace would bust him so it counts as 1, but then the 9 and 5 REALLY bust him, yet he wins.
amirite or should i be demoted to re-re?
i think I had like 17 in my hand. I might have busted as well, i forget now. But he should have busted and lost, right? TUBSWEETIE edited this message on 02/26/2008 3:37PM |
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| Posted On: 02/26/2008 3:36PM |
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Nope, each ace is going to be counted as 1…dealer is showing 20 |
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| Posted On: 02/26/2008 3:54PM |
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View CmdrSlack's Profile
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looks fine to me.. but damn that was a lucky hand for him. |
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| Posted On: 02/26/2008 4:01PM |
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View flamin kooz's Profile
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CmdrSlack Posted:
why would both aces count as one? the first ace should be 11 since the previous card was just 4, right? 4+11=15 which isn’t a bust. |
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| Posted On: 02/26/2008 4:04PM |
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ohhhhh so all the aces drop to 1. I get it now. I just played a couple rounds and had that happen in my favor a couple times. I should learn up on my card playing skills. |
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| Posted On: 02/26/2008 4:08PM |
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View TUBSWEETIE's Profile
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Yeah, Aces are 1 or 11, whichever you choose, at any time. You can change what they’re defined as, the typical blackjack game that updates after each card will bumume an Ace is 11 unless it’d bust, which is why it looks like you can’t switch them unless it’d bust you. |
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| Posted On: 02/26/2008 4:23PM |
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View SuperMo0's Profile
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Basically, he’s showing like this:
Ace (11) + 4 = 15 Ace (1) + 4 + Ace (1) = 6 Ace (1) + 4 + Ace (1) + 9 = 15 Ace (1) + 4 + Ace (1) + 9 + 6 = 20
That’s some good luck for a dealer, because the dealer has to stand on anything over 17. |
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| Posted On: 02/26/2008 6:31PM |
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View Bill_Murray_Fan_...'s Profile
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yes essentially aces are wild. even in the real blackjack, or atleast how i’ve played for years. |
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| Posted On: 02/26/2008 6:36PM |
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View flamin kooz's Profile
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I used to deal blackjack in the local casinos. bumuming Gamblebot’s playing by the same rules, aces are automatically counted as 11. If that would cause a bust, they’re dropped down to 1, one at a time, until a number below 21 is reached.
So this is how the hand was evaulated:
4 + A(11) = 15. Must hit. 4 + A(11) + A(1) = 16. Must hit. 4 + A(1) + A(1) + 9 = 15. Must hit. 4 + A(1) + A(1) + 9 + 5 = 20. Must stand.
Some more examples: A+A = 12 (must hit) A+A+10 = 12 (must hit) A+5 = 16 (must hit) A+6 = 17 (probably must stand, if like most casinos) |
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| Posted On: 02/26/2008 6:41PM |
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View MC Banhammer's Profile
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n00b65 Posted:
Ah, true. I dropped both aces to 1, but in most cases, the dealer would have to drop only ONE of them, giving them 16.
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| Posted On: 02/26/2008 6:47PM |
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View Bill_Murray_Fan_...'s Profile
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coolio dudes, thanks for the information. |
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| Posted On: 02/26/2008 8:58PM |
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