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Inertia Posted:
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Area of intersection = Area of Triangle + 2 * (Area inside 60 degree sector – Area of triangle)
Equivalent: Intersection = (2 * Area of 60 degree sector) – Area of triangle
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Area of 60 degree sector = (pi * r^2)/6 = (pi * 1)/6
Area of triangle = (sqrt 3)/4
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Intersection = (2 * (pi / 6)) – (sqrt 3)/4 .. = pi / 3 – (sqrt 3)/4 .. = 0.614 (3dp) |
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Posted On: 09/15/2009 11:27PM | View man-man's Profile | # |