C_Wenhoo Posted:

Not sure if my maths is off the mark, but:

If there are n participants:

Total prize = n bp

Number of winners = n / 3 (on average)

Each winner’s prize = n / (n / 3) = 3 bp

Chance of winning prize = 1/3

So if you join, your expected outcome is:

1/3 * 3bp – 1bp (entrance fee) = 0 bp

Meaning, if you join this contest many times, on average you will win 0bp. As good as a coin flip.

YOU ARE BAD AT MATHS. I don’t know why the **** you’re subtracting the 1BP for chances of winning. That’s stupid, it makes no sense.