Fie Posted:

I will give 1bp to somebody who can give me a simple answer to this.

toxx

MC Banhammer Posted:

I’m basically trying to determine if someone can use a roll of two dice to determine fairly between outcomes, by bumigning the result of odd to one choice, and even to another choice.

Yes you can. Here’s another way to think about it:

Chances one dice even: 0.5

Chances one dice odd: 0.5

So there are four possible outcomes:

Both dices even (adds to even): 0.5 x 0.5 = 0.25

Both dices odd (adds to even): 0.5 x 0.5 = 0.25

First dice even, second odd (adds to odd): 0.5 x 0.5 = 0.25

First dice odd, first even (adds to odd): 0.5 x 0.5 = 0.25

So adding up the probabilities:

even: 0.25 + 0.25 = 0.5

odd: 0.25 + 0.25 = 0.5

I think everyone is already clear on this, but the reason 2&1 and 1&2 are counted as “different” is because, compared to a value like 1&1, it happens twice as often. Therefore you must count is as two separate values, even though they add up to the same value.

Sneaky27, go grab two dice, throw them around for a couple hours, and record the results.

Fie Posted:

Will someone please just give me my chances of rolling bacon etc without being Log in to see images!

short answer: lower than they should be.

Ricket Posted:

2 – 1/36 possible outcomes (1 & 1)

3 – 2/36 possible outcomes (1 & 2, 2 & 1)

4 – 3/36 possible outcomes (1 & 3, 3 & 1, 2 & 2)

5 – 4/36 (1 & 4, 4 & 1, 2 & 3, 3 & 2)

6 – 5/36 (1 & 5, 5 & 1, 2 & 4, 4 & 2, 3 & 3)

7 – 6/36 (1 & 6, 6 & 1, 2 & 5, 5 & 2, 3 & 4, 4 & 3)

8 – 5/36 (2 & 6, 6 & 2, 3 & 5, 5 & 3, 4 & 4)

9 – 4/46 (3 & 6, 6 & 3, 4 & 5, 5 & 4)

10 – 3/36 (4 & 6, 6 & 4, 5 & 5)

11 – 2/36 (5 & 6, 6 & 5)

12 – 1/36 (6 & 6)

That’s 18/36 for even, and 18/36 for odds, so it’s a more complicated coin flip, basically.

Simple and to the point. Thx Ricket.

Sending BP. Contest closed.